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(A) In the electrophilic addition of $HBr$ to but$-1-$ene,the proton $(H^+)$ attacks the double bond to form a carbocation intermediate.Carbocation $A

Vedclass · Accepted Answer

Carbocation $B$ is more stable and formed relatively at a faster rate.

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(A) In the electrophilic addition of $HBr$ to but$-1-$ene,the proton $(H^+)$ attacks the double bond to form a carbocation intermediate.Carbocation $A$ is a primary $(1^\circ)$ carbocation $(CH_3-CH_2-CH_2-CH_2^+)$,while carbocation $B$ is a secondary $(2^\circ)$ carbocation $(CH_3-CH_2-CH^+-CH_3)$.Secondary carbocations are more stable than primary carbocations due to the inductive effect and hyperconjugation.Because carbocation $B$ is more stable,its formation has a lower activation energy,meaning it is formed at a faster rate.

Choose the correct statement regarding the formation of carbocations $A$ and $B$ given:
$CH_3-CH_2-CH=CH_2 + HBr \to CH_3-CH_2-CH_2-CH_2^+ + Br^-$ $(A)$
$CH_3-CH_2-CH=CH_2 + HBr \to CH_3-CH_2-CH^+-CH_3 + Br^-$ $(B)$

Similar Questions

Which of the following carbanions is the least stable?

Stability order of the following carbocations is:
$(i)$ $CH_3-C^{+}(CH_3)-CH_2-CH_3$
$(ii)$ $CH_3-CH^{+}-CH_3$
$(iii)$ $CH_3-C^{+}(CH_3)-CH_3$
$(iv)$ $Ph-CH^{+}-CH_3$

Assertion : Carbanions like ammonia have pyramidal shape.
Reason : The carbon atom carrying negative charge has an octet of electrons.

Which of the following species $(A)$,$(B)$,$(C)$,and $(D)$ contain an $sp^2$ hybridized carbon atom? $(A) CH_3^+$,$(B) CH_3^-$,$(C) \dot{C}H_3$,$(D) :CH_2$

The major products $A$ and $B$ in the following reactions are:

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Choose the correct statement regarding the formation of carbocations $A$ and $B$ given:$CH_3-CH_2-CH=CH_2 + HBr \to CH_3-CH_2-CH_2-CH_2^+ + Br^-$ $(A)$$CH_3-CH_2-CH=CH_2 + HBr \to CH_3-CH_2-CH^+-CH_3 + Br^-$ $(B)$